单片机之动态数码管的显示数字1-8
2020-07-17 来源:eefocus
C51单片机中的三种方法解决数码管的动态显示,使数码管显示1-8数字。三种方法的代码如下,此时读者需要十分注意你代码中引脚的先后顺序,否则可能达不到预期的效果.
#include #define uchar unsigned char #define uint unsigned int uchar code seg1[]={0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80}; //使用的是共阳极数码管 void delayms(uint i) { uchar j; while(i--) for(j=0;j<=125;j++); } void main() { while(1) { uchar i,j; P2=0x80; for(i=0;i<8;i++) { P2=_crol_(P2,1); P0=seg1[i]; delayms(1); } } } #include #define uchar unsigned char #define uint unsigned int uchar code seg1[]={0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80}; //使用的是共阳极数码管 uchar code seg2[]={0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80}; void delayms(uint i) { uchar j; while(i--) for(j=0;j<=125;j++); } void main() { while(1) { uchar i; for(i=0;i<8;i++) { P2=seg2[i]; P0=seg1[i]; delayms(1); } } #include #define uchar unsigned char #define uint unsigned int //uchar code seg1[]={0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80}; //使用的是共阳极数码管 //uchar code seg2[]={0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80}; void delayms(uint i) { uchar j; while(i--) for(j=0;j<=125;j++); } void main() { while(1) { P2=0x01; P0=0xf9; delayms(1); P2=0x02; P0=0xa4; delayms(1); P2=0x04; P0=0xb0; delayms(1); P2=0x08; P0=0x99; delayms(1); P2=0x10; P0=0x92; delayms(1); P2=0x20; P0=0x82; delayms(1); P2=0x40; P0=0xf8; delayms(1); P2=0x80; P0=0x80; delayms(1); } } 仿真图如下:
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