mini2440 Nandflash读问题

追风浪 2009-6-4 17:24 楼主

在研究nboot过程中，有几个地方不解：
我想让nboot有拷贝eboot到RAM得功能，因此需要进入loadboot函数进行拷贝。
#if 1 //本函数在友善之臂开发板中暂时没有用到
void loadboot(void)
{

DWORD dwSector, dwLength;       // Start Sector & Length
DWORD dwRAM, i;

dwSector=EBOOT_SECTOR; //2; //从block:2 page:0开始存放eboot
dwLength=3072;//一共6个block;block2-7;96K容量;如果eboot文件大于96K，需要修改该代码
dwRAM=0x30038000;//eboot load Start address;把NAND FLASH内容拷贝到0X30038000

while (dwLength)

{

         FMD_ReadSector(dwSector,(LPBYTE)dwRAM,NULL, 1);
dwSector++;
dwLength--;
         dwRAM += SECTOR_SIZE;//该程序目前不做校验 #define SECTOR_SIZE                   512

      }

Launch(0x30038000);//跳转到eboot，启动eboot，程序不会返回
}
#endif
loader.h中的相关定义
// NAND Boot (loads into SteppingStone) @ Block 0
#define NBOOT_BLOCK                0
#define NBOOT_BLOCK_SIZE          8 /*1 change by capbily for vivi */
#define NBOOT_SECTOR             BLOCK_TO_SECTOR(NBOOT_BLOCK)

// TOC @ Block 1
#define TOC_BLOCK                19 /*1 change by capbily for vivi */
#define TOC_BLOCK_SIZE             1
#define TOC_SECTOR                BLOCK_TO_SECTOR(TOC_BLOCK)

// Eboot @ Block 2
#define EBOOT_BLOCK                10 /*2 change by capbily for vivi */
#define EBOOT_SECTOR_SIZE          (11*PAGES_PER_BLOCK) /*FILE_TO_SECTOR_SIZE(EBOOT_RAM_IMAGE_SIZE)*///PAGES_PER_BLOCK=32
#define EBOOT_BLOCK_SIZE          11 /*SECTOR_TO_BLOCK(EBOOT_SECTOR_SIZE)*/
#define EBOOT_SECTOR             BLOCK_TO_SECTOR(EBOOT_BLOCK)

#define RESERVED_BOOT_BLOCKS    0x890// (NBOOT_BLOCK_SIZE + TOC_BLOCK_SIZE + EBOOT_BLOCK_SIZE)

// Images start after OEM Reserved Blocks
#define IMAGE_START_BLOCK          RESERVED_BOOT_BLOCKS
#define IMAGE_START_SECTOR       BLOCK_TO_SECTOR(IMAGE_START_BLOCK)

nand.h  #define BLOCK_TO_SECTOR(block)  ((block)  << 5 )
1、上面loadboot函数中为什么要循环3072次呢？FMD_ReadSector不是读512B吗？96K不是循环192次就可以了吗？
2、RESERVED_BOOT_BLOCKS(红色)为什么是0x890,NBOOT_BLOCK_SIZE + TOC_BLOCK_SIZE + EBOOT_BLOCK_SIZE=8+1+11=20块=20*32 SECTOR=320K?
3、BLOCK和SECTOR不是32倍关系吗？那eboot块数EBOOT_BLOCK_SIZE 是11，为什么EBOOT_SECTOR_SIZE是11*32呢？？