[讨论] 求DSPC2000 F28027eCAP完整项目文件

shiliu   2013-6-6 21:02 楼主
在论坛找了一个eCAP程序,改了一下,结果进不了中断,而且GPIO19脚还是高电平,求解决,代码如下:
void InitECapture()
{
   ECap1Regs.ECEINT.all = 0x0000; // Disable all capture interrupts
   ECap1Regs.ECCLR.all = 0xFFFF;  // Clear all CAP interrupt flags
   ECap1Regs.ECCTL1.bit.CAPLDEN = 0; // Disable CAP1-CAP4 register loads
   ECap1Regs.ECCTL2.bit.TSCTRSTOP = 0; // Make sure the counter is stopped
   // Configure peripheral registers
   ECap1Regs.ECCTL2.bit.CAP_APWM = 0;  //CAP mode
   ECap1Regs.ECCTL2.bit.CONT_ONESHT = 0; // continuous mode
   ECap1Regs.ECCTL2.bit.STOP_WRAP = 1;   // Stop at 2 events
   ECap1Regs.ECCTL1.bit.PRESCALE = 0;    // Divide by 1
   ECap1Regs.ECCTL1.bit.CAP1POL = 0;          // Rising edge
   ECap1Regs.ECCTL1.bit.CAP2POL = 0;          // Rising edge
   ECap1Regs.ECCTL1.bit.CTRRST1 = 1;          // Difference operation
   ECap1Regs.ECCTL1.bit.CTRRST2 = 0;          // Difference operation
   ECap1Regs.ECCTL2.bit.SYNCI_EN = 0;         // Enable sync in
   ECap1Regs.ECCTL2.bit.SYNCO_SEL = 3;        //  Disable sync out signal
   ECap1Regs.ECCTL1.bit.CAPLDEN = 1;          // Enable capture units
   ECap1Regs.ECCTL2.bit.TSCTRSTOP = 1;        // Start Counter
   ECap1Regs.ECEINT.bit.CEVT2 = 1;            // 2 events = interrupt
}
void main(void)
{
   InitSysCtrl();
   EALLOW;    //允许访问受保护的空间
      GpioCtrlRegs.GPADIR.bit.GPIO1=1;
      GpioDataRegs.GPADAT.bit.GPIO1=1;
      EDIS;
      InitECap1Gpio();
      InitECapture();
      EALLOW;  // This is needed to write to EALLOW protected registers
      PieVectTable.ECAP1_INT = &ecap1_isr;
      EDIS; // This is needed to disable write to EALLOW protected registers  // Enable CPU INT4 which is connected to ECAP1-4 INT:
      IER |= M_INT4;
      PieCtrlRegs.PIEIER4.bit.INTx1 = 1;
      // Enable eCAP INTn in the PIE: Group 3 interrupt 1-6
      EINT;   // Enable Global interrupt INTM
      ERTM;   // Enable Global realtime interrupt DBGM
      while(1);
}
interrupt void ecap1_isr(void)
{
//ECap1Count = ECap1Regs.CAP1;
   ECap2Count = ECap1Regs.CAP2;
   GpioDataRegs.GPADAT.bit.GPIO1=0;
//ECap1Regs.ECCLR.all = 0xFFFF;
   ECap1Regs.ECCLR.bit.CEVT2 = 1;
   ECap1Regs.ECCLR.bit.CEVT1 = 1;
   ECap1Regs.ECCLR.bit.INT = 1;
   PieCtrlRegs.PIEACK.all = PIEACK_GROUP4;

}

回复评论 (7)

看一下你的InitECap1Gpio初始化 :   InitECap1Gpio()
我感觉你可能InitECap1Gpio初始化有问题

[ 本帖最后由 ltbytyn 于 2013-6-7 11:43 编辑 ]
点赞  2013-6-7 11:25
还有你的表述里面应该是“GPIO1脚还是高电平”
点赞  2013-6-7 11:30

回复 沙发 ltbytyn 的帖子

那个初始化程序用的是本身自带的,和你发的那个帖子是一样的,
void InitECap1Gpio(void)

{

   EALLOW;

// GpioCtrlRegs.GPAPUD.bit.GPIO5=0;  //Enable pull-up on GPIO5 (CAP1)

   GpioCtrlRegs.GPAPUD.bit.GPIO19=0; // Enable pull-up on GPIO19 (CAP1)

// GpioCtrlRegs.GPAQSEL1.bit.GPIO5=0; // Synch to SYSCLKOUT GPIO5 (CAP1)

   GpioCtrlRegs.GPAQSEL2.bit.GPIO19=0;//Synch to SYSCLKOUT GPIO19(CAP1)

// GpioCtrlRegs.GPAMUX1.bit.GPIO5=3; // Configure GPIO5 as CAP1

   GpioCtrlRegs.GPAMUX2.bit.GPIO19=3; // Configure GPIO19 as CAP1

   EDIS;

}
程序里面的GPIO1我是用它来判断是否进入中断的啊,没有写错,就是GPIO19(捕获口)为高电压,进不了中断啊,求帮助,急求!!!!,非常感谢
点赞  2013-6-7 23:51
InitSysCtrl();
   EALLOW;    //允许访问受保护的空间
      GpioCtrlRegs.GPADIR.bit.GPIO1=1;
      GpioDataRegs.GPADAT.bit.GPIO1=1;
      EDIS;
      InitECap1Gpio();
      InitECapture();
      EALLOW;  // This is needed to write to EALLOW protected registers
      PieVectTable.ECAP1_INT = &ecap1_isr;
      EDIS; // This is needed to disable write to EALLOW protected registers  // Enable CPU INT4 which is connected to ECAP1-4 INT:
      IER |= M_INT4;
      PieCtrlRegs.PIEIER4.bit.INTx1 = 1;
      // Enable eCAP INTn in the PIE: Group 3 interrupt 1-6

        DINT;
        InitPieCtrl();
        IER = 0x0000;
        IFR = 0x0000;

        InitPieVectTable();
      EINT;   // Enable Global interrupt INTM
      ERTM;   // Enable Global realtime interrupt DBGM
      while(1);
}

IER、IFR、PIE初始化。调试时观察相应寄存器(PIE、ECAP等)的值是否正常。
点赞  2013-6-8 11:15

回复 楼主shiliu 的帖子

你现在调通了吗?
点赞  2013-9-4 16:11
你把GPIO19的上拉去掉,不要使能上拉即:
GpioCtrlRegs.GPAPUD.bit.GPIO19=1; //Disable pull-up on GPIO19 (CAP1)
这样做试试。
点赞  2013-9-4 18:58
分享的一个工程例子:https://bbs.eeworld.com.cn/thread-380183-1-1.html
芯片是F28335的,不过有参考价值。
点赞  2013-9-4 19:22
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