[求助] 请问如果ePWM上拉电阻使能的话会有什么后果？

dxj 2016-8-26 16:14 楼主

TI piccolo手册中“对于可以用作ePWM的输出的引脚，默认内部上拉电阻禁止使能“，请问如果ePWM上拉电阻使能的话会有什么后果？谢谢！

void InitEPwm1Gpio(void)
{
EALLOW;
/* Disable internal pull-up for the selected output pins
for reduced power consumption */
// Pull-ups can be enabled or disabled by the user.
// Comment out other unwanted lines.
GpioCtrlRegs.GPAPUD.bit.GPIO0 = 1; // Disable pull-up on GPIO0 (EPWM1A)
GpioCtrlRegs.GPAPUD.bit.GPIO1 = 1; // Disable pull-up on GPIO1 (EPWM1B)
/* Configure EPWM-1 pins using GPIO regs*/
// This specifies which of the possible GPIO pins will be EPWM1 functional pins.
// Comment out other unwanted lines.
GpioCtrlRegs.GPAMUX1.bit.GPIO0 = 1; // Configure GPIO0 as EPWM1A
GpioCtrlRegs.GPAMUX1.bit.GPIO1 = 1; // Configure GPIO1 as EPWM1B
EDIS;
}
改为
void InitEPwm1Gpio(void)
{
EALLOW;
/* Disable internal pull-up for the selected output pins
for reduced power consumption */
// Pull-ups can be enabled or disabled by the user.
// Comment out other unwanted lines.
GpioCtrlRegs.GPAPUD.bit.GPIO0 = 0 // Enable pull-up on GPIO0 (EPWM1A)
GpioCtrlRegs.GPAPUD.bit.GPIO1 = 0 // Enalbe pull-up on GPIO1 (EPWM1B)
/* Configure EPWM-1 pins using GPIO regs*/
// This specifies which of the possible GPIO pins will be EPWM1 functional pins.
// Comment out other unwanted lines.
GpioCtrlRegs.GPAMUX1.bit.GPIO0 = 1; // Configure GPIO0 as EPWM1A
GpioCtrlRegs.GPAMUX1.bit.GPIO1 = 1; // Configure GPIO1 as EPWM1B
EDIS;
}