ARM Flash烧写问题

charon2 2008-11-19 00:05 楼主

我最近在调试一块S3C4510的开发板。配置如下：Flash：SST39VF160 一片。Flash中原有一个Bootloader。上电后，串口显示如下：
Compex BIOS for SAMSUNG S3C4510B (build 20040121)
Main Menu

1 - Run uClinux
2 - Load image to sdram and Run uClinux
3 - Burn image to flash
4 - Update BIOS(Pay attention!!)
5 - Read ram data

Please Select:

现在我想使用HJTAG烧写Flash确怎么也不能读出Flash的ID。
使用AXD调试器（配合HJTAG）调试发现，上电后，memory 0x1000000位置开始为Flash的内容(flash的地址)。但是比较奇怪，我使用setmem 0x1000000 0x0000 32这之类的命令时，发现flash对应的内存空间数据也会被修改。
使用如下代码在AXD中调试时发现，代码装载到0x00开始的空间且可以执行，但是无法读出flash的ID。代码如下

#define UINT16 unsigned short
#define AM_START_ADDR       0x1000000       //此处为Flash的起始地址，设为1000000
#define AM_ADDR_UNLOCK1       0x5555
#define AM_ADDR_UNLOCK2       0x2aaa
#define AM_DATA_UNLOCK1       0xaaaa
#define AM_DATA_UNLOCK2       0x5555
#define AM_SETUP_WRITE       0xaaaa
#define AM_SETUP_ERASE       0x8080
#define AM_CHIP_ERASE       0x1010
#define AM_SECTOR_ERASE    0x3030
#define AM_RESET    0xf0f0

int Main()
{
int i;
*((volatile UINT16 *)AM_START_ADDR+ AM_ADDR_UNLOCK1) = AM_DATA_UNLOCK1;    //aaaa
*((volatile UINT16 *)AM_START_ADDR+ AM_ADDR_UNLOCK2) = AM_DATA_UNLOCK2; //5555
*((volatile UINT16 *)AM_START_ADDR+ AM_ADDR_UNLOCK1) = AM_SETUP_ERASE;      //9090
/*
*((volatile UINT16 *)AM_START_ADDR+ AM_ADDR_UNLOCK1) = AM_DATA_UNLOCK1;
*((volatile UINT16 *)AM_START_ADDR+ AM_ADDR_UNLOCK2) = AM_DATA_UNLOCK2;
   *((volatile UINT16 *)AM_START_ADDR+ AM_ADDR_UNLOCK1) = AM_CHIP_ERASE; //1010
   */
   for (i=0; i<5000; i++)
   {
   ;
   }
return(0);
}

请各位高手给我解惑啊。这个问题我看了好几天了，不知道问题出在哪了。

非常感谢！

回复评论（7）

沙发 cocalli

怎么没人啊，自己顶一个

点赞 2008-11-19 00:13

板凳 high47

使用JTAG和AXD只能把BOOT放到内存。至于要实现烧写flash，必须自己在boot加入烧写程序。
1 - Run uClinux
2 - Load image to sdram and Run uClinux
3 - Burn image to flash
4 - Update BIOS(Pay attention!!)
5 - Read ram data
从上面几个菜单看出你的boot并不支持烧写flash，要想实现，自己写些程序吧。

点赞 2008-11-19 08:37

4楼 Hellenlee

点赞 2008-11-19 08:37

5楼 paradise721

我是用如下程序来操作的。也是从网上找到的修改的。
#define UINT16 unsigned short
#define AM_START_ADDR       0x1000000       //此处为Flash的起始地址，设为1000000
#define AM_ADDR_UNLOCK1       0x5555
#define AM_ADDR_UNLOCK2       0x2aaa
#define AM_DATA_UNLOCK1       0xaaaa
#define AM_DATA_UNLOCK2       0x5555
#define AM_SETUP_WRITE       0xaaaa
#define AM_SETUP_ERASE       0x8080
#define AM_CHIP_ERASE       0x1010
#define AM_SECTOR_ERASE 0x3030
#define AM_RESET 0xf0f0

int Main()
{
int i;
*((volatile UINT16 *)AM_START_ADDR+ AM_ADDR_UNLOCK1) = AM_DATA_UNLOCK1;  //aaaa
*((volatile UINT16 *)AM_START_ADDR+ AM_ADDR_UNLOCK2) = AM_DATA_UNLOCK2; //5555
*((volatile UINT16 *)AM_START_ADDR+ AM_ADDR_UNLOCK1) = AM_SETUP_ERASE; //9090
/*
*((volatile UINT16 *)AM_START_ADDR+ AM_ADDR_UNLOCK1) = AM_DATA_UNLOCK1;
*((volatile UINT16 *)AM_START_ADDR+ AM_ADDR_UNLOCK2) = AM_DATA_UNLOCK2;
  *((volatile UINT16 *)AM_START_ADDR+ AM_ADDR_UNLOCK1) = AM_CHIP_ERASE; //1010
  */
  for (i=0; i <5000; i++)
  {
  ;
  }
return(0);
}

不知道是怎么回事。请各位牛人赐教啊

点赞 2008-11-19 12:35